Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
For a square of side length L, the perimeter is:
P = 4*L
Then if the perimeter of our square is 36 units, we have:
36 units = 4*L
(36 units)/4 = L = 9 units.
Now we know that one vertex of the square is located at (3, 5)
Then another vertex of the square can be at:
A distance of 9 units of this point (such that these vertices are connected by one side of the square)
Some examples can be:
(3 + 9, 5) = (12, 5)
or
(3, 5 + 9) = (3, 14)
These are the simpler options, there are a lot of other possible points that can be another vertes (we can have a circle of radius 9 units centered in the point (3, 5), all these points can be another vertex of the square).
We also can have a vertex that is connected by the diagonal, this point can be:
(3 + 9, 5 + 9) = (12, 14)
or
(3 - 9, 5 - 9) = (-6, -4)
Again, there are a lot of other possible points that can be this vertex (A circle of radius √2*9 units centered in the point (3, 5)).
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.