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Sagot :
Answer:
- [tex]C)~A+ \frac{B}{x-3} +\frac{c}{(x-3)^2}[/tex]
Step-by-step explanation:
→ [tex]\frac{(7x^2-40x+52)}{(x^2-6x+9)}[/tex]
→ [tex]\frac{7x^2-40x+52}{x^2-2.3x+(3)^2}[/tex]
→ [tex]\frac{7x^2-40x+52}{(x-3)^2}[/tex]
So, your answer is C
[tex]----------[/tex]
hope it helps...
have a great day!!
The partial fractions is to start with the simplified, and "decompose" the expression into initial polynomial fractions, and the calculation is as follows:
Partial fractions:
- The degree of the fraction must be strictly less than the degree of the denominator required to conduct partial fractions.
- It's critical to keep that in mind. So, once we've established that partial fractions are possible, we factor the denominator to the greatest extent possible.
[tex]\to \frac{7x^2-40x+52}{x^2-6x+9}\\\\\to \frac{7x^2-40x+52}{x^2-(3x-3x)+9}\\\\\to \frac{7x^2-40x+52}{x^2-3x+3x+9}\\\\\to \frac{7x^2-40x+52}{x(x-3)+3(x+3)}\\\\\to \frac{7x^2-40x+52}{(x-3)^2}\\\\\to \frac{7x^2-40x+52}{(x-3)^2}\\\\\to A+ \frac{B}{(x-3)}+\frac{C}{(x-3)^2}\\\\[/tex]
Find out more about the partial fractions here:
brainly.com/question/24594390
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