Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A scientist distilled a quantity of water to use in an experiment. How much water did he collect if the condensation process released 9040 J of energy? H2O (l) -> H2O (g) ΔHv=2260 J/g a 0.0138 mol b 0.222 mol c 4.00 mol d 0.250 mol I really need the answer plz

Sagot :

kaylamorgan20

Answer:

I know this is very late I am sorry, but

I believe your answer would be C) 4.00 mol.

Correct me if I am wrong.

Explanation:

9040 divided by 2260= 4

pstnonsonjoku

0.222 moles of water  released 9040 J of energy.

The heat of vaporization is defined as the heat required to convert 1 g of a substance from liquid to vapor. We are told that the heat of vaporization of water is 2260 J/g.

Hence;

1g of water releases  2260 J of heat

xg of water releases  9040 J of heat

x = 1g ×  9040 J /2260 J

x = 4 g

1 mole of water contains 18 g

x moles of water contains 4 g

x = 1 mole  × 4 g/18 g

x = 0.222 moles

Learn more: https://brainly.com/question/10165688

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.