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A scientist distilled a quantity of water to use in an experiment. How much water did he collect if the condensation process released 9040 J of energy? H2O (l) -> H2O (g) ΔHv=2260 J/g a 0.0138 mol b 0.222 mol c 4.00 mol d 0.250 mol I really need the answer plz

Sagot :

kaylamorgan20

Answer:

I know this is very late I am sorry, but

I believe your answer would be C) 4.00 mol.

Correct me if I am wrong.

Explanation:

9040 divided by 2260= 4

pstnonsonjoku

0.222 moles of water  released 9040 J of energy.

The heat of vaporization is defined as the heat required to convert 1 g of a substance from liquid to vapor. We are told that the heat of vaporization of water is 2260 J/g.

Hence;

1g of water releases  2260 J of heat

xg of water releases  9040 J of heat

x = 1g ×  9040 J /2260 J

x = 4 g

1 mole of water contains 18 g

x moles of water contains 4 g

x = 1 mole  × 4 g/18 g

x = 0.222 moles

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