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30 POINTS! PLEASE HELP I ONLY GOT 3 QUESTIONS LEFT.
Preston says the sequence of transformations that maps triangle ABC onto triangle DEF is: rotate it 180 degrees about the origin, and then translate it up 7 units.

Chanel says the sequence of transformations that maps triangle ABC onto triangle DEF is: reflect it across the x-axis, then reflect it across the y-axis, and then translate it up 6 units and left 1 unit.

Part F
Complete the table to find the rule for the reflection, the coordinates of triangle ABC, and the coordinates of the reflected image, triangle A′B′C′.
Original Coordinates New Coordinates
(x, y) ( , )
A( , ) A′( , )
B( , ) B′( , )
C( , ) C′( , )

Part H
Complete the table to find the rule for the reflection, the coordinates of triangle A′B′C′, and the coordinates of the reflected image, triangle A″B″C″.
Original Coordinates New Coordinates
(x, y) ( , )
A'( , ) A"( , )
B'( , ) B"( , )
C'( , ) C"( , )

Part J
Complete the table to find the rule for the translation, the coordinates of triangle A″B″C″, and the coordinates of the translated image, triangle A‴B‴C‴.
Original Coordinates New Coordinates
(x, y) ( , )
A″( , ) A‴( , )
B″( , ) B‴( , )
C″( , ) C‴( , )

30 POINTS PLEASE HELP I ONLY GOT 3 QUESTIONS LEFT Preston Says The Sequence Of Transformations That Maps Triangle ABC Onto Triangle DEF Is Rotate It 180 Degrees class=

Sagot :

Answer:

Preston has it almost right. His would work if he shifted up 6 and left 1, or if he had pivoted about the point (-½,-½) then shifted up 7

I think that the parts F, H, J have to do with Chanel's method, which gets us to the correct transformation.

Part F reflecting across the x axis leaves x identical but negates y

  (x, y)      (x, -y)

A(-4, 5)  A′(-4, -5)

B(-3, 1)  B′(-3, -1)

C(-5, 2)  C′(-5, -2)

Part H reflecting across the y axis negates the x value and leaves y identical

    (x, y)      (-x, y)

A'(-4, -5)  A"(4, -5)

B'(-3, -1)  B"(3, -1)

C'(-5, -2)  C"(5, -2)

Part J translation adds -1 to the x value and +6 to the y value

    (x, y)      (x - 1, y + 6)

A″(4, -5)  A‴(3, 1)  = D

B″(3, -1)  B‴(2, 5) = E

C″(5, -2)  C‴(4, 4) = F

Step-by-step explanation:

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