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Sagot :
Answer:
Preston has it almost right. His would work if he shifted up 6 and left 1, or if he had pivoted about the point (-½,-½) then shifted up 7
I think that the parts F, H, J have to do with Chanel's method, which gets us to the correct transformation.
Part F reflecting across the x axis leaves x identical but negates y
(x, y) (x, -y)
A(-4, 5) A′(-4, -5)
B(-3, 1) B′(-3, -1)
C(-5, 2) C′(-5, -2)
Part H reflecting across the y axis negates the x value and leaves y identical
(x, y) (-x, y)
A'(-4, -5) A"(4, -5)
B'(-3, -1) B"(3, -1)
C'(-5, -2) C"(5, -2)
Part J translation adds -1 to the x value and +6 to the y value
(x, y) (x - 1, y + 6)
A″(4, -5) A‴(3, 1) = D
B″(3, -1) B‴(2, 5) = E
C″(5, -2) C‴(4, 4) = F
Step-by-step explanation:
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