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What is the slope of the line 5y = –3x + 10 ?

Sagot :

Divide 5 by both sides. So you get y=(-3/5)x + 2
The slope is (-3/5).
[tex]5y=-3x+10\\ y=-\frac{3}{5}x+2\\\\ \boxed{m=-\frac{3}{5}}[/tex]
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