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if cosØ=1/6 what are the values of sinØ and tanØ?

Sagot :

Answer:

Step-by-step explanation:

cos theta = (adjacent side) / (hypotenuse) = 1/6.  The adjacent side has length 1 and the hypotenuse length 6.  The opposite side has length

√(6^2 - 1^2) = ÷√35

and so sin theta = (opp side) / (hypotenuse) = (√35) / 6

and tan theta = [(√35) / 6] / (1/6), or √35