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Given cos 0= -1/2 and angle 0 is in quadrant two what is the exact value of sin 0  in simplest form

Sagot :

adityareddykarra

Answer:

[tex]-\sqrt{7/4}[/tex]

Step-by-step explanation:

XxDeanxX

[tex] \sin( \theta) = \frac{ \sqrt{3} }{2} [/tex]

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