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What is the exponential regression equation that fits these data?
х
у
-4
0.025
-3
0.075
-2
0.25
-1
0.70
0
3
1
8
2
20
3
60
4
160
A. y= 4.90x2 + 14.44x - 4.69
B. y = 3.02 · 2.26%
C. y = 2.01 • 3.80%
D. y = 2.26. 3.02%

What Is The Exponential Regression Equation That Fits These Data Х У 4 0025 3 0075 2 025 1 070 0 3 1 8 2 20 3 60 4 160 A Y 490x2 1444x 469 B Y 302 226 C Y 201 3 class=

Sagot :

Answer: it is y=2.26x3.02^x

Step-by-step explanation:

Option D is correct.

What is exponential regression?

An exponential regression is the process of finding the equation of the exponential function that fits best for a set of data.

The general form for the exponential regression equation

[tex]y = ae^{bx}[/tex]

According to the question

We have a data.

Let the exponential regression equation be [tex]y = ae^{bx}[/tex]

Take two values of  x and y  from the given data for finding the value of a and [tex]e^{b}[/tex].

substitute y = 0.025 and x = -4 in [tex]y = ae^{bx}[/tex] we get

[tex]0.025 = ae^{-4b}...(1)[/tex]

similarly ,substitute y = 0.075 and x = -3 in [tex]y = ae^{bx}[/tex] we get

[tex]0.075 = ae^{-3b} ....(2)[/tex]

from equation 1 and 2

[tex]\frac{0.025}{0.075} = \frac{ae^{-4b} }{ae^{-3b} }[/tex]

⇒[tex]\0.333 = e^{-b}[/tex]

⇒[tex]ln(o.33) = -b[/tex]

⇒[tex]-(1,1086) = -b[/tex]

b = 1.1086

Therefore,

[tex]e^{b} = (2.718)^{1.1086} = 3.0041[/tex]

and substitute b = 1.1086 and [tex]e^{b} = 3.0041[/tex] in either equation 1 or 2, we get

a = 2.2

Thus, the exponential regression equation will be

[tex]y = (2.2)3.041^{x}[/tex]

Hence, option D is the correct one.

Learn more about exponential regression equation here:

https://brainly.com/question/11169800

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