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Helpp pls
A small balloon with a 1.36E-9 C charge is placed a distance of 0.4100 m from a 1.99E-7 C charge. Determine the electric field intensity at the location of the balloon. Round to the appropriate number of sig figs, and do not put your answer in scientific notation.


Sagot :

Answer:

The intensity of the electric field is

[tex]|E|=10654.37 \:N/C[/tex]

Explanation:

The electric field equation is given by:

[tex]|E|=k\frac{q}{d^{2}}[/tex]

Where:

  • k is the Coulomb constant
  • q is the charge at 0.4100 m from the balloon
  • d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

[tex]|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}[/tex]

[tex]|E|=10654.37 \:N/C[/tex]

I hope it helps you!

Answer:

10650

Explanation:

just round that answer to four significant figures and you get that answer

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