Answered

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Subtract: [tex]\frac{6}{2x^2+8x} -\frac{x}{4x^2+12-16} =\frac{6}{2x(x+4)} -\frac{x}{4(x+4)(x-1)} =\frac{6*2(x-1)}{2x(x+4)*2(x-1)} -\frac{x*x}{4(x+4)(x-1)*x}[/tex]

A:[tex]\frac{-2x^2+12x-12}{2(x+4)(x-1)}[/tex]
B:[tex]\frac{-x^2+6x-6}{2(x+4)(x-1)}[/tex]
C:[tex]\frac{-2x^2+12x-12}{4(x+4)(x-1)}[/tex]
D:[tex]\frac{-x^2+12x-12}{4x(x+4)(x-1)}[/tex]

Sagot :

ghaithgh

Step-by-step explanation:

I think D

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