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In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=71°, and RS = 2.5 feet. Find the length of SQ to the nearest tenth of a foot.

Sagot :

sqdancefan

9514 1404 393

Answer:

  0.9 ft

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

  tan(71°) = (2.5 ft)/SQ . . . . . . . . fill in the given values

  SQ = (2.5 ft)/tan(71°) ≈ 0.8608 ft

The length of SQ is about 0.9 feet.

View image sqdancefan
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