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Find a formula for the sequence 3, 9/4, 27/7, 81/10,... in sigma notation​

Sagot :

sqdancefan

9514 1404 393

Answer:

  [tex]\displaystyle S_n=\sum_{k=1}^n{\frac{3^k}{3k-2}}[/tex]

Step-by-step explanation:

The sequence terms appear to have numerators that are powers of 3, and denominators that are a linear (arithmetic) sequence with a first term of 1 and a common difference of 3.

  numerator: 3^x

  denominator: 1 +3(n -1) = 3n-2

Then the sum of n terms of the sequence can be described by ...

  [tex]\displaystyle \boxed{S_n=\sum_{k=1}^n{\frac{3^k}{3k-2}}}[/tex]

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