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A town has a population of 18000 and grows at 2% every year. What will be the population after 11 years, to the nearest whole number?

Sagot :

Answer:

21960 people

Step-by-step explanation:

so first you find 2 percent of 18000 which is 360, then you multiply that by 11 because thats the amount of years and when you do that you get 3960

when you add the population grwoth over 11 years plus the current population you get 21960

2008809agreen

Answer:

~22381

Step-by-step explanation:

a=starting value = 18000

r=rate = 2%=0.02

Exponential Growth:

b=1+r=1+0.02=1.02

b=1+r=1+0.02=1.02

Write Exponential Function:

y=18000(1.02)^x

y=18000(1.02)

x

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=18000(1.02)^{11}

y=18000(1.02)

11

Evauate:

y= 22380.73755

y=22380.73755

Round:

y\approx 22381

y≈22381

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