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Sagot :
Answer:
We fail to reject the Null and conclude that the standard deviation of the contributions of all sanitation workers is not greater than that of all workers living in the city.
Step-by-step explanation:
σ = 1.40 ; σ² = 1.40² = 1.96
H0 : σ² = 1.96
H0 : σ² > 1.96
Given that:
Sample size, n = 12
Population Standard deviation, σ = 1.40
Sample standard deviation, s = 1.75
α = 0.01
The test statistic :
χ² = [(n-1)s²] ÷ σ²
χ² = [(12 - 1) * 1.75²] ÷ 1.40²
χ² = (11 * 3.0625) ÷ 1.96
χ² = 33.6875 / 1.96
χ² = 17.1875
χ² = 17.19
Using the Pvalue from Chisquare score calculator;
df = n - 1 ; 12 - 1 = 11
Pvalue ; χ²(17.19, 11) = 0.10238
Since Pvalue > α ; We fail to reject the Null and conclude that the standard deviation of the contributions of all sanitation workers is not greater than that of all workers living in the city.
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