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what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)?

Sagot :

Answer:

y = -5/3x + 20

Step-by-step explanation:

y = -5/3x + b

-5 = -5/3(15) + b

-5 = -25 + b

20 = b

y = -5/3x + 20

Answer:

In other words.. The fourth option D.

Step-by-step explanation:

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