Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Explanation:
The concentration of the solution is given by :
[tex][C]=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}[/tex]
We have:
Concentration of copper (II) nitrate solution = [tex][Cu(NO_3)_2]=2.41 M[/tex]
The volume of solution = 4.12 mL
1 mL= 0.001 L
[tex]4.12 mL= 4.12\times 0.001 L= 0.00412 L[/tex]
Moles of copper (II) nitrate in solution = n
[tex]2.41=\frac{n}{0.00412 L}=0.0099292 mol[/tex]
Moles of copper (II) nitrate in solution = 0.0099292 mol
1 Mole of copper(II) nitrate has 1 mole of copper then 0.0099292 moles of copper(II) nitrate will have :
[tex]1\times 0.0099292 mol= 0.0099292 \text{ mol of Cu}[/tex]
Mass of 0.0099292 moles of copper:
[tex]=0.0099292 mol\times 63.55 g/mol=0.63100 g\approx 0.631 g[/tex]
This mass of copper present in the solution is the theoretical mass of copper present in the given copper(II) nitrate solution.
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.