Answer:
a) [tex]\omega=9.10*10^{-4}rad/sec[/tex]
b) [tex]V=1.8217*10^{-3}[/tex]
Explanation:
From the question we are told that:
Mass of woman [tex]M_w=55kg[/tex]
Radius of merry go round [tex]r=2.0m[/tex]
Rotational inertia [tex]i= 1250 kg-m2[/tex]
Mass of rock [tex]M_r=350g \approx 0.350kg[/tex]
Speed of rock [tex]V_r=2.0m/s[/tex]
Tangent angle to the outer edge [tex]\theta=1[/tex]
a)
Generally the equation for conservation of momentum is mathematically given by
[tex]M_r(ucos\theta)r=(I+M_wr^2)\omega[/tex]
[tex]0.350(2.0cos1)(2.0)=(1250+(55)(2.0)^2)\omega[/tex]
[tex]1.3998=1470\omega\\\omega=\frac{1.339}{1470}[/tex]
[tex]\omega=9.10*10^{-4}rad/sec[/tex]
b)
Generally the equation for linear speed V is mathematically given by
[tex]V=r\omega\\V=2.0*9.10*10^{-4}[/tex]
[tex]V=1.8217*10^{-3}[/tex]
