Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The limit of x approaching infinite of a function gives it's horizontal assymptote. We use this to solve the question, getting the following answer:
Because Limit of f (x) as x approaches plus-or-minus infinity = 16, the function has a horizontal asymptote at y = 16.
Horizontal asymptote:
An horizontal asymptote is the value of y given by:
[tex]y = \lim_{x \rightarrow \infty} f(x)[/tex]
In this question:
[tex]f(x) = \frac{16x^2 - 35}{x^2 - 5}[/tex]
The horizontal asymptote is:
[tex]y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{16x^2 - 35}{x^2 - 5}[/tex]
Considering it is a limit of x going to infinite, we just consider the terms with the highest exponents both in the numerator and in the denominator, so:
[tex]y = \lim_{x \rightarrow \infty} \frac{16x^2 - 35}{x^2 - 5} = \lim_{x \rightarrow \infty} \frac{16x^2}{x^2} = \lim_{x \rightarrow \infty} 16 = 16[/tex]
Thus, the correct answer is:
Because Limit of f (x) as x approaches plus-or-minus infinity = 16, the function has a horizontal asymptote at y = 16.
From the graph of the function, given at the end of this answer, you can check that as x goes to infinity, y(green line) approches 16(blue line).
For more on infinite limits, you can check https://brainly.com/question/23335924
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
