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Sagot :
Answer:
pH of the base solution after the chemist has added 213.6 mL of the HNO3 solution to it is 9.96
Explanation:
Calculating the moles of dimethylamine
Moles of dimethylamine = molairty * volume in L = 0.63*0.0992 = 0.0625moles
Moles of HNO3 = molarity * volume in L = 0.25*0.2136 = 0.0534 moles
The balanced chemical equation is
(CH3)2NH + HNO3 -------------------> (CH3)2NH2^+ + NO3^-
I 0.0625 0.0534 0
C -0.0534 - 0.0534 0.0534
E 0.0091 0 0.0534
As we know ,
POH = Pkb + log[(CH3)2NH2^+]/[(CH3)2NH]
= 3.27 + log0.0534/0.0091
= 3.27+ 0.768
= 4.038
PH = 14-POH
= 14-4.038 = 9.96
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