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A normal distribution has a mean 7 of and a standard deviation of 2. Use the​ 68-95-99.7 rule to find the percentage of values in the distribution between and .
What is the percentage of values in the distribution between 7 and 9​?

Sagot :

Answer:  34%  (approximate)

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Explanation:

We have 7 at the center. Going 2 units to the left of center gets us to 7-2 = 5. Going 2 units to the right of center gets us to 7+2 = 9.

Since the mean is 7 and the standard deviation is 2, this tells us that the values 5 and 9 are exactly one standard deviation away from the mean.

Due to the empirical rule (aka 68-95-99.7 rule), we just found that roughly 68% of the population is between 5 and 9.

Half of this is 68/2 = 34%, so this is the percent of values between 7 and 9.

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