Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The distance between the points (x₁,y₁) and (x₂,y₂):
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](-10,3) \\ x_1=-10 \\ y_1=3 \\ \\ (-10,12) \\ x_2=-10 \\ y_2=12 \\ \\ d=\sqrt{(-10+10)^2+(12-3)^2}=\sqrt{0+9^2}=\sqrt{9^2}=9[/tex]
Another method:
The points have the same x-coordinate so they lie on the same line. y-coordinates are positive so you just subtract 3 from 12. See the picture in the attachment.
The answer is 9.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](-10,3) \\ x_1=-10 \\ y_1=3 \\ \\ (-10,12) \\ x_2=-10 \\ y_2=12 \\ \\ d=\sqrt{(-10+10)^2+(12-3)^2}=\sqrt{0+9^2}=\sqrt{9^2}=9[/tex]
Another method:
The points have the same x-coordinate so they lie on the same line. y-coordinates are positive so you just subtract 3 from 12. See the picture in the attachment.
The answer is 9.

The way to solve it can be shorter :)
Just look, that these points have got the same x-coordinate,
so they lie on the same line, which is parallel to the OY axis,
So your taks is only find different in y-coordinate. That is
12-3 = 9
And this is answer :)
Just look, that these points have got the same x-coordinate,
so they lie on the same line, which is parallel to the OY axis,
So your taks is only find different in y-coordinate. That is
12-3 = 9
And this is answer :)
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.