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Sagot :
The distance between the points (x₁,y₁) and (x₂,y₂):
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](-10,3) \\ x_1=-10 \\ y_1=3 \\ \\ (-10,12) \\ x_2=-10 \\ y_2=12 \\ \\ d=\sqrt{(-10+10)^2+(12-3)^2}=\sqrt{0+9^2}=\sqrt{9^2}=9[/tex]
Another method:
The points have the same x-coordinate so they lie on the same line. y-coordinates are positive so you just subtract 3 from 12. See the picture in the attachment.
The answer is 9.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](-10,3) \\ x_1=-10 \\ y_1=3 \\ \\ (-10,12) \\ x_2=-10 \\ y_2=12 \\ \\ d=\sqrt{(-10+10)^2+(12-3)^2}=\sqrt{0+9^2}=\sqrt{9^2}=9[/tex]
Another method:
The points have the same x-coordinate so they lie on the same line. y-coordinates are positive so you just subtract 3 from 12. See the picture in the attachment.
The answer is 9.

The way to solve it can be shorter :)
Just look, that these points have got the same x-coordinate,
so they lie on the same line, which is parallel to the OY axis,
So your taks is only find different in y-coordinate. That is
12-3 = 9
And this is answer :)
Just look, that these points have got the same x-coordinate,
so they lie on the same line, which is parallel to the OY axis,
So your taks is only find different in y-coordinate. That is
12-3 = 9
And this is answer :)
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