Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

a jumping spider jumps from a log on the ground below. its height , h, in cm as a function of time ,t, in seconds since it jumped can be modeled by the function h(f)=-490t2+75t+12. when does the spider land on the ground? and what is the height of the spider 0.05 s after it jumps?

Sagot :

Inorder to find the height, you miust plug in 0.05s for all times (t)
h(f) = -490t^2 + 75t + 12
h(f) = -490 • 0.05^2 + 75 • 0.05 + 12

Next follow PEMDAS from left to right.
(MD reversible, AS reversible)
(parentheses, exponents, multiply, divide, add, subtract)
parentheses~ nothing to simplify with parentheses
exponents~ h(f) = -490 • 0.0025 + 75 • 0.05 +12
multiply~  h(f) = -1.225 + 3.75 +12
divide~ nothing to simplify with division
add~ h(f) = 14.525
subtract~ nothing to simplify with subtraction

DON'T FORGET UNITS!

Answer: h(f) = 14.525 cm



Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.