Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

a jumping spider jumps from a log on the ground below. its height , h, in cm as a function of time ,t, in seconds since it jumped can be modeled by the function h(f)=-490t2+75t+12. when does the spider land on the ground? and what is the height of the spider 0.05 s after it jumps?

Sagot :

bayjo98241
Inorder to find the height, you miust plug in 0.05s for all times (t)
h(f) = -490t^2 + 75t + 12
h(f) = -490 • 0.05^2 + 75 • 0.05 + 12

Next follow PEMDAS from left to right.
(MD reversible, AS reversible)
(parentheses, exponents, multiply, divide, add, subtract)
parentheses~ nothing to simplify with parentheses
exponents~ h(f) = -490 • 0.0025 + 75 • 0.05 +12
multiply~  h(f) = -1.225 + 3.75 +12
divide~ nothing to simplify with division
add~ h(f) = 14.525
subtract~ nothing to simplify with subtraction

DON'T FORGET UNITS!

Answer: h(f) = 14.525 cm



Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.