Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The hypotenuse has got to have the longest side in a right angled triangle.
Say, A=Adjacent, O=Opposite, H=Hypotenuse
A²+O²=H²
Therefore,
A²<H²
O²<H²
As this is the case:
H>A
H>O
Say, A=Adjacent, O=Opposite, H=Hypotenuse
A²+O²=H²
Therefore,
A²<H²
O²<H²
As this is the case:
H>A
H>O
Other proof:
Look at the picture.
[tex]sin\alpha\in (0;\ 1)\\\\sin\alpha=\frac{b}{h} < 1\ therefore\ h > b\\\\cos\alpha\in(0;\ 1)\\\\cos\alpha=\frac{a}{h} < 1\ therefore\ h > a\\\\the\ conclusion:\ h > a\ and\ h > b\ \Rightarrow h\ has\ to\ be\ the\ longest\ side\\of\ a\ right\ triangle.[/tex]
Look at the picture.
[tex]sin\alpha\in (0;\ 1)\\\\sin\alpha=\frac{b}{h} < 1\ therefore\ h > b\\\\cos\alpha\in(0;\ 1)\\\\cos\alpha=\frac{a}{h} < 1\ therefore\ h > a\\\\the\ conclusion:\ h > a\ and\ h > b\ \Rightarrow h\ has\ to\ be\ the\ longest\ side\\of\ a\ right\ triangle.[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.