Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Solving Systems of Equations by Substitution

y=1/2x+5

y=-3/2x-7


Sagot :

[tex]\left\{\begin{array}{ccc}y=\frac{1}{2}x+5\\y=-\frac{3}{2}x-7\end{array}\right\\\\subtitute:\\\\\frac{1}{2}x+5=-\frac{3}{2}x-7\ \ \ \ |subtract\ 5\ from\ both\ sides\\\\\frac{1}{2}x=-\frac{3}{2}x-12\ \ \ \ |add\ \frac{3}{2}x\ to\ both\ sides\\\\\frac{4}{2}x=-12\\\\2x=-12\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-6}\\\\subtitute\ value\ of\ "x"\ to\ first\ equation:\\\\y=\frac{1}{2}\cdot(-6)+5=-3+5=\boxed2\\\\Answer:\boxed{\boxed{x=-6\ and\ y=2}}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.