Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
[tex]log\frac{5\cdot10^{-3}}{2\cdot10}}=log\left(\frac{5}{2}\cdot\frac{10^{-3}}{10}\right)=log(2.5\cdot10^{-3-1}})=log(2.5\cdot10^{-4})=(*)\\\\use\ log(a\cdot b)=loga+logb\ and\ loga^b=b\cdot loga\\\\(*)=log2.5+log10^{-4}=log2.5-4log10=log2.5-4\\\vdots\\log2.5=log\frac{25}{10}=log25-log10=log25-1=log5^2-1=2log5-1\\\\therefore\\\\(*)=2log5-1-4=2log5-5[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.