24x^2 - 45x - 21 = 0

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02-01-2015
Mathematics

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24x^2 - 45x - 21 = 0

Sagot :

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eu99li eu99li · Answer 1 · 2015-01-02T12:54:30-05:00

eu99li eu99li

02-01-2015

[tex]24x^2-45x-21=0 3(8x^2-15x-7)=0 /:3 8x^2-15x-7=0 a=8... b=-15.... c=-7 delta= b^2-4ac=449 x_1= \frac{15- \sqrt{449} }{16} x_2= \frac{15+ \sqrt{449} }{16} [/tex]√ΔΔΔΔΔΔΔΔΔ

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konrad509 konrad509 · Answer 2 · 2015-01-02T13:43:44-05:00

konrad509 konrad509

02-01-2015

[tex]24x^2-45x-21=0\\ 3(8x^2-15x-7)=0\\ 8x^2-15x-7=0\\ \Delta=(-15)^2-4\cdot8\cdot(-7)=225+224=449\\ \sqrt{\Delta}=\sqrt{449}\\ x_1=\dfrac{-(-15)-\sqrt{449}}{2\cdot8}=\dfrac{15-\sqrt{449}}{16}\\ x_2=\dfrac{-(-15)+\sqrt{449}}{2\cdot8}=\dfrac{15+\sqrt{449}}{16}[/tex]

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