Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Calcium hydride reacts with water to form hydrogen gas and calcium hydroxide. How many grams of calcium hydride are needed to generate 53.5 liters of hydrogen gas if the pressure is 814 torr at 21*C.

Sagot :

The Equation is CaH2(s)+2H2O(l)-->Ca(OH)2(aq)+2H2(g)

so,

moles of H2 generated = PV / RT

R = 62.363 L Torr K−1 mol−1

number of moles = 814 * 53.5 / 62.363 * 293

= 2.38 moles

looking at the equation these came from 2.38 /2 moles of CaH2 or 1.19 moles

Molar mass of CaH2 is 42.0943 g/mol

so mass of CaH2 = 1.19 X 42.1 = 50.01g

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.