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Sagot :

4(x+5)=x+8
4x+4*5=x+8
4x+20=x+8
4x-x+20=x+8-x
3x+20-20=8-20
3x=-12
3x/3=(-12)/3
x=-4
so 4(x+5)=x+8
first we distribute
using the distributive property of multiplication which is a(b+c)=(ab)+(ac)

4(x+5) is also (4x)+(4(5))=4x+20

4x+20=x+8
subtract x from both sides
3x+20=8
subtract 20 from both sides
3x=-12
divide both sides by 3
x=-4

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