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Sagot :
c=chicken sandwich
v=bowl of vegetable soup
so Chris: 2c+3v=50 and
Jim: 1c+2v=9.5
so 2c+3v=50 and c+2v=9.5
c+2v=9.5
subtract 2 v from both sides
c=9.5-2v
subsitute c=9.5-2v for c in 2c+3v=50
2(9.5-2v)+3v=50
distribute
19-4v+3v=50
add like terms
19-v=50
add v to both sides
19=50+v
subtract 50 from both sides
-31=v
the value of foods are never negative so there is no solution
v=bowl of vegetable soup
so Chris: 2c+3v=50 and
Jim: 1c+2v=9.5
so 2c+3v=50 and c+2v=9.5
c+2v=9.5
subtract 2 v from both sides
c=9.5-2v
subsitute c=9.5-2v for c in 2c+3v=50
2(9.5-2v)+3v=50
distribute
19-4v+3v=50
add like terms
19-v=50
add v to both sides
19=50+v
subtract 50 from both sides
-31=v
the value of foods are never negative so there is no solution
2c + 3v = $50 ;
1c + 2v =$9.50 / * 2 ;
2c + 4v =$19; 2c + 3v + v =$19; $50 + v =$19; v = -$31; False, because v > 0 ;
There is something wrong with this problem !
1c + 2v =$9.50 / * 2 ;
2c + 4v =$19; 2c + 3v + v =$19; $50 + v =$19; v = -$31; False, because v > 0 ;
There is something wrong with this problem !
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