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Sagot :
so consectuve even numbers
we know that one even number plus 2= another even number so we want to find 3 consecutive even numbers that add up to 96 or
x is the first number
x+2 is the second number
x+4 is the third number
x+x+2+x+4=96
3x+6=96
subtract 6 from both sides
3x=90
divide both sides by 3
x=30
the first number is 30
x+2=32=second number
x+4=34=third number
the numbers are 30,32,34
we know that one even number plus 2= another even number so we want to find 3 consecutive even numbers that add up to 96 or
x is the first number
x+2 is the second number
x+4 is the third number
x+x+2+x+4=96
3x+6=96
subtract 6 from both sides
3x=90
divide both sides by 3
x=30
the first number is 30
x+2=32=second number
x+4=34=third number
the numbers are 30,32,34
Let me show you how I like to do problems like this:
-- If I just needed three numbers that add up to 96, the easiest way
to do it would be to find 1/3 of 96 . That's 32, so the three numbers
could be 32, 32, and 32.
-- If you want three consecutive even numbers, just take 2 away from
one of those numbers, and add it on to a different one.
Now you have 30, 32, and 34, and you haven't changed their sum.
-- If I just needed three numbers that add up to 96, the easiest way
to do it would be to find 1/3 of 96 . That's 32, so the three numbers
could be 32, 32, and 32.
-- If you want three consecutive even numbers, just take 2 away from
one of those numbers, and add it on to a different one.
Now you have 30, 32, and 34, and you haven't changed their sum.
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