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Sagot :
a) The distance between towns P and Q can be found with the information about the bus. The bus left P at 7:30 and arrived at Q at 12:00, making his trip 4:30, or 4.5 hours, long. The problem says the bus is driving at 60 km/h. Therefore, the bus drives at 60 km/h for 4.5 hours. To find the distance traveled:
[tex](4.5 hrs)(\frac{60 km}{1 hr}) = 270 km[/tex]
So, the answer to a) is 270 km.
b) The speed of the car can be found now that the distance between the towns is known. We know that the car left town Q at 7:45 and reached town P at 10:45, making the car's trip 3 hours long. Therefore, the car traveled 270 km in 3 hours.
[tex]speed = \frac{distance}{time}[/tex], so
[tex]speed = \frac{270km}{3hrs}[/tex] = 90 km/hr
[tex](4.5 hrs)(\frac{60 km}{1 hr}) = 270 km[/tex]
So, the answer to a) is 270 km.
b) The speed of the car can be found now that the distance between the towns is known. We know that the car left town Q at 7:45 and reached town P at 10:45, making the car's trip 3 hours long. Therefore, the car traveled 270 km in 3 hours.
[tex]speed = \frac{distance}{time}[/tex], so
[tex]speed = \frac{270km}{3hrs}[/tex] = 90 km/hr
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