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The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes. Find the probability that a randomly selected passenger has a waiting time
greater than 1.25 minutes.Find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes.


Sagot :

Answer:

0.8214

Step-by-step explanation:

We have

F(x) = 1/b-a

With b = 7

And a = 0

Such that we have

1/7-0

= 1/7

Probability of x> 1.25

7-1.25

= 5.75

1/7 x 5.75

= 0.8214

Therefore the probability that a randomly selected passenger has a waiting time more than 1.25 minutes is = 0.8214.

Thank you!