Answered

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What are the solutions to the quadratic equation x2-16=0

Sagot :

theleangreenbean

Answer:

x = -4, 4

Step-by-step explanation:

Hi there!

[tex]x^2-16=0[/tex]

Rewrite 16:

[tex]x^2-4^2=0[/tex]

The difference of squares rule states that [tex]a^2-b^2=(a+b)(a-b)[/tex]. With this, apply the difference of squares to the equation:

[tex](x+4)(x-4)=0[/tex]

The zero-product property states that if the product of two numbers is 0, then one of the numbers must be equal to zero. Set each term equal to 0 and find the solutions:

[tex]x+4=0\\x=-4[/tex]

[tex]x-4=0\\x=4[/tex]

Therefore, the solutions are -4 and 4.

I hope this helps!

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