Answered

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Answer:

1.8 × 10² J

Explanation:

Step 1: Given data

  • Mass of the rock (m): 20 g
  • Initial temperature: 10 °C
  • Final temperature: 29 °C
  • Specific heat capacity of granite (c): 0.48 J/g.°C

Step 2: Calculate the amount of heat absorbed (q)

We will use the following expression.

q = m × c × ΔT

q = 20 g × 0.48 J/g.°C × (29 °C - 10 °C) = 1.8 × 10² J

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