Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Sagot :

maacastrobr

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

  • V₁T₂=V₂T₁

Where in this case:

  • V₁ = 852 mL
  • T₂ = 200 K
  • V₂ = ?
  • T₁ = 298 K

We input the data:

  • 852 mL * 200 K = V₂ * 298 K

And solve for V₂:

  • V₂ = 571.81 mL

The new volume would be 571.81 mL.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.