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If a spinner for a game is spun once, there is a 25% chance it will land on
orange. What is the chance that the spinner will not land on orange on both
the first and second spin in a game? Calculate the probability as a decimal
rounded to the nearest TENTH.

Sagot :

MrRoyal

Answer:

[tex]Pr = 0.6[/tex]

Step-by-step explanation:

Given

Let

[tex]O \to Orange[/tex]

So:

[tex]P(O) = 25\%[/tex] --- probability of O

[tex]n=2[/tex] --- Number of spin

Using the complement rule, the probability that a spin will not land on orange is:

[tex]P(O') = 1 - P(O)[/tex]

[tex]P(O') = 1 - 25\%[/tex]

Express as decimal

[tex]P(O') = 1 - 0.25[/tex]

[tex]P(O') = 0.75[/tex]

On two spins, the probability that it will not land on orange is:

[tex]Pr = P(O') * P(O')[/tex]

So, we have:

[tex]Pr = 0.75* 0.75[/tex]

[tex]Pr = 0.5625[/tex]

[tex]Pr = 0.6[/tex] --- approximated

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