prissyn2344
Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first​

Sagot :

hnori22003

2n + 1 , 2n + 3 , 2n + 5

____________________________

( 2n + 5 ) + ( 2n + 3 ) = 5 × ( 2n + 1 ) - 15

4n + 8 = 10n + 5 - 15

4n + 8 = 10n - 10

Add both sides 10

4n + 8 + 10 = 10n - 10 + 10

4n + 18 = 10n

Subtract both sides 4n

4n - 4n + 18 = 10n - 4n

18 = 6n

Divide both sides by 6

18 ÷ 6 = 6n ÷ 6

n = 3

_________________________________

Thus that three numbers are :

2(3) + 1 , 2(3) + 3 , 2(3) + 5

6 + 1 , 6 + 3 , 6 + 5

7 , 9 , 11

And we're done ....

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.