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Sagot :

What is this type of math called please and what year/grade if you don’t mind me asking so I can be prepared
Leora03

Answer:

[tex]m = \frac{5}{2} [/tex]

Step-by-step explanation:

Here are the laws which would be used in this question:

Indices:

• [tex] \sqrt{a} = {a}^{ \frac{1}{2} } [/tex]

• [tex] \frac{1}{a} = {a}^{ - 1} [/tex]

Logarithm

• [tex] log_{a}( {x}^{n} ) = n log_{a}(x) [/tex]

[tex] log_{m}( \sqrt{2} ) + log_{m}(8) + log_{m}( \frac{1}{2} ) [/tex]

[tex] = log_{m}( {2}^{ \frac{1}{2} } ) + log_{m}( {2}^{3} ) + log_{m}( {2}^{ - 1} ) [/tex]

[tex] = \frac{1}{2} log_{m}(2) + 3 log_{m}(2) - log_{m}(2) [/tex]

[tex] = \frac{5}{2} log_{m}(2) [/tex]

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