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bhadelsimron19

Answer:

Step-by-step explanation:

cos theta=4[tex]\sqrt{2}[/tex]/7

so here adjacent=4[tex]\sqrt{2}[/tex] ,hypotenuse=7 ,opposite=?

h^2=p^2+b^2

7^2=(4[tex]\sqrt{2}[/tex] )^2+b^2

49-32=b^2

[tex]\sqrt{17}[/tex] =b

sin theta=opposite/hypotenuse

=[tex]\sqrt{17[/tex]/7

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