bananahen21
Answered

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Simplify. State any restrictions on the variables.
[tex]\frac{x^2+9x+18}{x+6}[/tex]

Sagot :

Medunno13

Answer: [tex]x+3, x \neq -6[/tex]

Step-by-step explanation:

The denominator cannot equal 0, so [tex]x \neq -6[/tex].

Simplfying,

[tex]\frac{x^2 +9x+18}{x+6}=\frac{(x+6)(x+3)}{x+6}=x+3[/tex]

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