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Answered

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(give the answer or I'll report) please solve it with the steps​

Give The Answer Or Ill Report Please Solve It With The Steps class=

Sagot :

AMH2005

Answer:

The required elastic potential energy is 0.068J

Explanation:

Given,

Spring force constant, k= 3.4 N/M

Spring stretch length/ Displacement, x= 0.2m

We know,

Elastic potential energy, V= [tex]\frac{1}{2} kx^{2}[/tex]

                                           =[tex]\frac{1}{2}*3.4*(0.2)^{2}[/tex]

                                           =[tex]\frac{0.136}{2}[/tex]

                                           =0.068

∴The required elastic potential energy is 0.068J

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