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Sagot :
Answer:
a. 686g of H2SO4 are present.
b. 3.321L would be made
Explanation:
a. Molarity, M, is an unit of concentration defined as the ratio between moles of solute (In this case H2SO4) and liters of solution. The moles of H2SO4 in 3.5L of 2.0M H2SO4 are:
3.5L * (2.0mol H2SO4 / L) = 7.0 moles H2SO4
The mass is obtained using molar mass of H2SO4 -98g/mol-:
7.0 moles H2SO4 * (98g / mol) = 686g of H2SO4 are present
b. The density of H2SO4 is 1.83g/mL. The volume of 2.0M H2SO4 per liter of solution is:
2.0mol H2SO4 / L * (98g / mol) * (1mL / 1.83g) = 107mL of H2SO4 are present per liter of solution. In 3L there are:
3L (107mL / L) = 321mL = 0.321L of H2SO4 must be added to 3L of water to produce 2.0M H2SO4. The total volume is:
3L + 0.321L = 3.321L would be made
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