matthewesther2019
Answered

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Integrate Sin(3x)Cos(3x) dx

Sagot :

xero099

Answer:

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

Step-by-step explanation:

We use integration by substitution to obtain the integral, where:

[tex]u = \sin 3x[/tex], [tex]du = 3\cdot \cos 3x\,dx[/tex]

[tex]I = \int {\sin 3x\cdot \cos 3x} \, dx[/tex]

[tex]I = \frac{1}{3} \int {u} \, du[/tex]

[tex]I = \frac{1}{6}\cdot u^{2} + C[/tex]

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

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