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If f (2) = 60 – 5.
find x for f (x) = 13

Sagot :

Answer:

The required value of [tex]x[/tex] is [tex]\frac{3}{5}[/tex]

Step-by-step explanation:

Given,

f (2) = 60 – 5

      = (30 X 2) - 5

∴ f (x) = [tex]30x-5[/tex]

Again,

f (x) = 13 [given]

[tex]30x-5=13\\or, 30x= 13+5\\or, 30x=18\\or, x=\frac{18}{30} \\\\or, x=\frac{3}{5} \\[/tex]

∴[tex]x=\frac{3}{5}[/tex]

Verification:

f (x) = [tex]30x-5[/tex]

∴ f ([tex]\frac{3}{5}[/tex]) = (30 X [tex]\frac{3}{5}[/tex]) - 5

         = 18 - 5

         = 13

∴ The required value of [tex]x[/tex] is [tex]\frac{3}{5}[/tex]