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Sagot :
Step-by-step explanation:
Maths
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if 2
2008
−2
2007
−2
2006
+2
2005
=k ⋅2
2005
then the value of k is equal to
Answer
Correct option is
B
3
2
2008
−2
2007
−2
2006
+2
2005
=k⋅2
2005
⇒[2
2008
−2
2006
]−[2
2007
−2
2005
]=k⋅2
2005
⇒2
2006
(2
2
−1)−2
2005
(2
2
−1)=k⋅2
2005
⇒3(2
2006
−2
2005
)=k⋅2
2005
⇒3[2
2005
(2−1)]=k⋅2
2005
⇒3(2
2005
)=k⋅2
2005
On comparing, we get
k=3
Hence, Option B is correct.
Answer:
k = 3
Step-by-step explanation:
[tex]2^{2008}-2^{2007}-2^{2006}+2^{2005}=k \times 2^{2005}[/tex]
[tex]=> (2^{2005} \times 2^3) - (2^{2005} \times 2^2) - (2^{2005} \times 2^1) + 2^{2005} = k \times 2^{2005}[/tex]
- Take [tex]2^{2005}[/tex] common from all the terms in L.H.S.
[tex]=> 2^{2005}(2^3 - 2^2 - 2^1 + 1) = k \times 2^{2005}[/tex]
- Divide both the sides by [tex]2^{2005}[/tex].
[tex]=> \frac{2^{2005}(2^3 - 2^2 - 2^1 + 1)}{2^{2005}} = \frac{k \times 2^{2005}}{2^{2005}}[/tex]
[tex]=> 2^3 - 2^2 - 2^1 + 1 = k[/tex]
- Expand the terms in L.H.S.
[tex]=> 8 - 4 - 2 + 1 = k[/tex]
[tex]=> k = 3[/tex]
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