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Let f (x) = 10/x-4
What is the average rate of change of f (x) from 2 to 8 ?

Enter your response as a decimal.

Sagot :

Numenius

Answer:

1.875

Step-by-step explanation:

The rate of change is the derivative of the function.

[tex]f(x) = \frac{10}{x-4}\\\\f'(x)=10\times \frac {d}{dx}\frac{1}{x-4}\\\\f'(x)=\frac{-10}{(x-4)^{2}}\\\\f'(2) = \frac{-10}{(2-4)^{2}} =-2.5\\\\f'(8)= \frac{-10}{(8-4)^{2}} =-0.625\\[/tex]

So, the rate of change is

f'(8) -  f'(2) = - 0.625 + 2.5 = 1.875

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