Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

a tin has asquare base whose sides measures 32 cm .the vertical sides are 50cm high.cake mixture is poured into the tin and leveled off at the 38 cm mark above the base


(i)the capacity of the tin


(ii)the volume of the cake mixture in the tin in cm^3

(iii)volume of the space unoccupied by the cake in cm^3

Sagot :

Numenius

Answer:

(a) V = 51200 cubic cm

(b) V' = 38912 cubic cm

(c) V'' = V - V' = 12288 cubic cm

Step-by-step explanation:

side of the square base, s = 32 cm

height, h = 50 cm

height of cake mixture, h' = 38 cm

(a) The capacity of the tin is the volume.  

Capacity of tin, V =  s x s x h = 32 x 32 x 50 = 51200 cubic cm

(b) The volume of the cake mixture is

V' =  s x s x h'

V' = 32 x 32 x 38 = 38912 cubic cm

(c) Volume of unoccupied space is

V'' = V - V' = 51200 - 38912 = 12288 cubic cm

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.