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Nine times a number, subtracted from the square of the number, is 36. Find the two numbers.

Sagot :

Answer:

- 3 and 12

Step-by-step explanation:

let n be the number , then

n² - 9n = 36 ( subtract 36 from both sides )

n² - 9n - 36 = 0

Consider the factors of the constant term (- 36) which sum to give the coefficient of the n- term (- 9)

The factors are - 12 and + 3 , since

- 12 × 3 = - 36 and - 12 + 3 = - 9 , then

(n - 12)(n + 3) = 0

Equate each factor to zero and solve for n

n - 12 = 0 ⇒ n = 12

n + 3 = 0 ⇒ n = - 3

The 2 numbers are - 3 and 12

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