Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 106.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 432.0 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 241 kg

Sagot :

Cricetus

Answer:

"1155 N" is the appropriate solution.

Explanation:

Given:

Acceleration,

[tex]a=3 \ m/s^2[/tex]

Forces resisting motion,

[tex]F_f=432 \ N[/tex]

Mass,

[tex]m = 241 \ kg[/tex]

By using Newton's second law, we get

⇒ [tex]F-F_f=ma[/tex]

Or,

⇒         [tex]F=ma+F_f[/tex]

By putting the values, we get

⇒             [tex]=(3\times 241)+432[/tex]

⇒             [tex]=723+432[/tex]

⇒             [tex]=1155 \ N[/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.