2qnkmnqq5r
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

The volume of gas in a balloon is 1.90L at 21.0°C.The balloon is heated, causing it to expand to a volume of 5.70L. what is the new temperature of the gas inside the balloon?

Sagot :

Answer: The new temperature is [tex]63^{o}C[/tex].

Explanation:

Given: [tex]V_{1}[/tex] = 1.90 L,    [tex]T_{1} = 21.0^{o}C[/tex]

[tex]V_{2}[/tex] = 5.70 L,         [tex]T_{2} = ?\\[/tex]

Formula used to calculate new temperature is as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{1.90 L}{21.0^{o}C} = \frac{5.70 L}{T_{2}}\\T_{2} = 63^{o}C[/tex]

Thus, we can conclude that the new temperature is [tex]63^{o}C[/tex].

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.