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The volume of gas in a balloon is 1.90L at 21.0°C.The balloon is heated, causing it to expand to a volume of 5.70L. what is the new temperature of the gas inside the balloon?

Sagot :

Answer: The new temperature is [tex]63^{o}C[/tex].

Explanation:

Given: [tex]V_{1}[/tex] = 1.90 L,    [tex]T_{1} = 21.0^{o}C[/tex]

[tex]V_{2}[/tex] = 5.70 L,         [tex]T_{2} = ?\\[/tex]

Formula used to calculate new temperature is as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{1.90 L}{21.0^{o}C} = \frac{5.70 L}{T_{2}}\\T_{2} = 63^{o}C[/tex]

Thus, we can conclude that the new temperature is [tex]63^{o}C[/tex].

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